Determine the pOH of a 0.291 M LIOH solution at 25°C O 13.71 O 13.46 O...

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Answer 1

Answer #1

Hi there, the formula for strong bases like KOH, LiOH, NaOH is

LiOH ==> Li^+ + OH-

1 mol LiOH gives 1 mol Li^+ & 1 mol OH- ions, so concentration of OH- = concentration of LiOH

pOH = -log[OH-] = -log[0.291 M] = 0.536

Answer: pOH of 0.291 M LiOH = 0.536

Determine the pOH of a 0.291 M LiOH solution at 25°C. 13.77 13.46 o 0.28 0.536 e 0.29+

Hope this helped you!

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Answer 2

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