Question

QUESTION 7 A 97.5 mL solution is 0.975 M HCl. What is the concentration after 50 mL of water is added to the solution? Round answer to 3 decimal places and do not include units. QUESTION 8 A 0.07 M HCl solution is used to simulate the acid concentration of the stomach. How many liters of "stomach acid" react with a tablet containing 0.44 g of magnesium hydroxide (58.33 g/mol)? Round answer to two sig figs and do not include units.

Answer 1

0 Formula: mv, = Mave On & Mi= initial concentration V = " volume M2 = final concentration V₂ = " volume. Mi = 0.975M V = 97.5 m2 V2 = initial volume & volume of water added = 97.5 mL + 50mL - 147.5 mL Now, X 3 0.975 mx 97.5 mL = M2 x 147.5 mL - M₂ = 9.975 x 97.5 147.5 m i M₂ = 0.644 m & final concentration M = 0.644 m. Hence, the answer is 10.644 !

given mass No. of moles = 1 molar mass holar mass of Mg (014)2 = 58.32 g/mol. ir 0.44 g Mg(OH)₂ = cow 0.44 g C. 58.33 g/mol Mg(OH, = 0.0075 mole Mg(OH)₂ Reaction : Mg(OH)₂ + 2HQ mq Cl2 + 2H₂O. soo 0.0075 mole Mg10H) will react with (2X0.0075) mole Hu= 0.0150 mole Ha.

Oo 07 M Ha means. - i. 0.07 mole 0.015 more He is in 1000 he will be in mL soln plooo xoo 015)mL 0.07 = 214.28 me 21-428 x 10 mL 21x10lme Hence as we need 21x10 mL soin. The answer is. [21x10']