1)
AgNO3 (aq) + KCl (aq) ---------> AgCl (s) + KNO3 (aq)
169.87 g 143.32 g
10.35 g ??
mass of AgCl formed = 10.35 x 143.32 / 169.87
= 8.73 g
% yield = (actual / theoretical) x 100
77.15 = (actual / 8.73) x 100
actual yield = 6.73 g
amount of AgCl formed = 6.73 g
Determine the amount of AgCl formed when 10.35 g of AgNO3 reacts with excess KCl to...
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