Question

. Nitroglycerin (C3H5(NO3)3C3H5(NO3)3) is a principal component of dynamite. The decomposition reaction of nitroglycerine produces four different gases and releases a large amount of thermal energy.

4C3H5(NO3)3⟶12CO2(g)+10H2O(g)+6N2(g)+O2(g)4C3H5(NO3)3⟶12CO2(g)+10H2O(g)+6N2(g)+O2(g)

Calculate the number of grams of each product produced when 45.0 g nitroglycerine decompose

Answer 1

Decomposition reaction of nitroglycerin 4 C ₂ H 5 (NO3)₂ - 12 co₂+ 10 H₂O + 6N₂ + O₂ Mwts 4x227 . 12xuy 10x18 6x28 32 = 908 528 180 168 32 From Equation de composition of 908 g of nitroglycerin gives 528 9 of co2, 180 g of H2O, 1689 N 3290₂ - 45g of nitroglycerin ou de composition gilles Holy much of the products.? No. of grams of co₂= 45 x 528= 26. 16749 908 No of grams of H2O= 45 x 180 = 8.829 908 No. of grams of N₂= 45 x 168= 8.326 g 908 No. of grams of 2= 45 I x 32=1.5859 g. 908