Question

In the following molecular orbital diagram of HCl: MO diagram for HCI molecule 0 3pz H1s Tin Tnb CI 3p ОзрZ CI 3s Onb Which i
ОзрZ 11 СІ Зѕ Onb Which is the LUMO? Select one: o a. Пnb o b. Зp3s о с. 1s Onb а*3pz е. 3s of. Озру o g. 15 ооо
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Answer #1

We can see from the molecular orbital diagram of HCl that the lowest unoccupied molecular orbital (LUMO) here is antibonding sigma 3pz. So the correct option is d.

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