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Ammonia, NH3(g)NH3(g), at a pressure of 1.13 bar, is placed in a container at a certain...

Ammonia, NH3(g)NH3(g), at a pressure of 1.13 bar, is placed in a container at a certain temperature. When equilibrium is established at that temperature, the pressure of H2(g)H2(g) is 0.620 bar.

Part A

Determine the value of KPKP for the decomposition of NH3NH3 at that temperature:

2NH3(g)⇌3H2(g)+N2(g)2NH3(g)⇌3H2(g)+N2(g)

Express your answer in squared bars to three significant figures.

Please show steps and the final units in bar^2

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Answer #1

he objective is to Determine the value of kp. Given data il Reaction O NH3 (9) E 34219)+ N2 (9) Initial pressure, po 1.13 bar® 0.620 bar 0.620 bar*0.620 bar * 0.2066 Hoy 2066 Hey [1.5434 bar 4 1.5434 bar] 0.04923 bar 2.38 2 08 borr - 0.02067 bory bo

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