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A 25.0 mL volume of a 0.200 M N2H4 solution (Kb = 1.70 × 10−6) is...

A 25.0 mL volume of a 0.200 M N2H4 solution (Kb = 1.70 × 10−6) is titrated to the equivalence point with 0.100 M HCl. What is the pH of this solution at the equivalence point? The titration is:

N2H4 + HCl xid-114312785_2 N2H5+ + Cl−
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Answer #1

Here is the solution of your question. If you have any doubt or need any clarification please comment in comment box and will definitely resolve your query. If you find useful please upvote it. Thanks in advance.

At equivalence point mmol of Nally = mmol of Hel 25ml x0.20M = 0.10M X V(mi). Vcamos = 50ml Naty HCL Natisci I (mmal 5 mmol 5

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