Question

As part of an investigation on the synthesis of various nitrogen and oxygen containing heterocycles, a series of amino alcohols were treated with aldehydes and ketones. In one of the runs, a colorless liquid product was obtained. A small sample of this liquid product was subjected to combustion analysis. The results indicated that the product contained 55.35% carbon, 10.84% hydrogen, and 21.52% nitrogen. Which structure is consistent with this combustion analysis data? Circle the structure of your choice NO -N SON a NHN0 ha ana -N No FW 101.15 FW 118.13 FW 130.19 FW 188.27 A chemist decided to explore the diastereoselectivity associated with the reaction shown below upon reduction of both carbonyl groups of the diketone 1,2-diphenylethane-1,2-dione with NaBH. Following the same procedure that you used for the reduction of (+/-) benzoin with NaBH4, the chemist first treated 5.00 mmols of 1,2-diphenylethane-1,2-dione with 4.00 mmols of NaBHA followed by treatment with excess water. The reaction afforded a 70% yield of 1,2- diphenylethane-1,2-diol (a.k.a. hydrobenzoin) along with NaB(OH)as the by-product. In the spaces provided, place appropriate coefficients to come up with a balanced chemical equation. Also, draw the Lewis structure of the product in the space provided. Note: no need to use wedged and dashed bonds! 0 0 + NaBH4 + H20 — NaB(OH) 1,2-diphenylethane-1,2-dione 1,2-diphenylethane-1,2-diol Given that an excess quantity of water was used in this reaction, which reactant is the limiting reagent (LR): 1,2- diphenylethane-1,2-dione or NaBHA? Clearly show your calculations/logic and indicate your conclusion below.

Answer 1

Tue results indicated that the product contained 155.384. Carlion, 10.847.44 21.524 N. which structure is consistent with this combustion analysis data? Cicle the structure of your chouse wass - nooncar (1245=60 = no. f H = 11 - 1 = 60 *100=59.319. 181=1 no. lol 1x 16 = 16 fw 101.15 - nood N=1 '1XM=4 1.= 11x100 = 10.8 74. 10115 Tolik 10 - 16 KID = 15.04. lor t o l. N = 14 x 100 = 13.84 lol.1 1 o No. 9 = c = 4 & 4x12=60 4.6260 X 100 - 507942 f.w=118.13 No. 1 H= 10 % u = 10 x 100 = 8.464. - 2 Noitetilas 972 X162 32 vodo olo o 32 10.13 10 =27.081 No. of N=2 8 14x2 = 28.un 499 % N 20 X100. = 23.70.). 110.13 No a n o q c = 6 = 12x6=12 42x100 215.300 (3019 Fw=130.19 No 1 = 14 No nu-19 : %u2 14 X100 130.19 210.25%

= 12.2842 x 100 07 - 16 = 130.19 Nywa 28 x 100 = 21.507. 130.19 06 = 9 : 1289 = 1089 - 010 6 = lod x100 108.27 -57.36.1 MW188.27 Nid H= 20 20 X 100 lo H = 100.27 10.624.1 7. N= 200 x 100 a 14:07 t r 0.27 2010 = 32 x 100 16.9941: Buod 188.27 So from all the above calculation, it is ИМ, In the spaces prouded place the appropriate coefficent to come up with a balanced chemical gulation. Also draw the levis structured the product in the space provided.

classmate Date Page + Wabalu + 4 0,0 Na BH4 + 4 H₂O + 6). Na B (OH), herich 112-diowe or Magent is the NaBly? limiting reagent: (*2-diphenylethan 5.00 mmals A 1,2-diphenylethan 1,2-dione with 4.00 manals a NaBny were used 4 rot of the product was obtained. Quice that with from the balanced equation, it is suggested 2 male of foa-diphenylethan 1,2-dione reacts . I milles on Na Bhu. so 5. oommates of bone reactant needs 5 oommels in Nasty Howenes in the reaction only 4.00 miniales is being used. So Na Bhy is town in елелал. На 1,2-і раманлаш - 92 -сем и luniting. As for every s.rom reales q its only S = 2.50 muales 9 Na Hy are theoretically needed. OOO