Homework Answers
According to the balanced reaction,
2 mole Fe require 6 mole HCl
2×55.8 g = 111.6 g Fe require 6×36.5 = 219 g HCl
266 g Fe require 219×266/111.6 g HCl
= 521.99 g HCl
Since we have less HCl available hence, HCl is limiting reagent.
6 mole HCl give 2 mole FeCl3
219 g HCl give 2×162.2 = 324.4 g FeCl3
222 g HCl give 324.4×222/219 g FeCl3
= 329 g FeCl3
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