Question

Lab 7 - Determination of the Ksp of 2000 Calcium Hydroxide Name Madeline Cardu eve Section_02 Date Team Member(s) Data Part 1: Preparation of Dilute Hydrochloric Acid 1. Concentration of stock HCl solution: 100M 2. Concentration of diluted HCl solution: _0.0400 M (Hint: Use M Vı-M2V2) Show your work below. Part 2: Determination of Ksp for Ca(OH)2 at Room Temperature 1. Volume of Ca(OH), solution used: OML

Answer 1

Facuer pation OP Ksp for Co0H), in boiling contes Deteemination 1 Trial volume op die of dil. Hei added a 3-6401 -0.003641 ocenteation of dil-HCl = 0.0400m volume of Ca(OH), Solution - 5 ml. 0.00 moles of HOI Used CXV = 0.0400m x 0. 003644 = 0.0001456 moles For every moles of cat)we need a moles of HCl QHCl(aq) + Ca(OH), 5 2 HAO () + cacla (ar) : No. of moles of cao. = No. of moles of HOI = 0.0001456 moles = 0.0000728 moles CACH) concenteation of CaOH). = No.of moles Volume of Solution in L = 0.0000708 moles 0.0145 m ca @H2209 = content + Boticas . [cap] - [cacorba] Cow] = { xf caco).] Ksp = [cart] @hje CS canned with CamScanner

concentration of cat. 0.0145 m OH = 2*0.0145 m - 0.029 m k sp - (0.0145 m) 0.029)? = 0.000012 12x100 Trial 2 Volume of dil. HCI added = 3.6G MI= 0.00366 L con- of dil. Hal = 0.04 m volume of ca@H), Soln. added = 5m1 = 0.005L moles of HCI used = OxV = 0.04mxo.00366L - 0.000146 moles of HCL No.of moles of coloit), = 0.000146 moles = 0.000073 moles cacola con of CaOH). = no.of moleg of calon volume in litee = 0.000073 moles 0.005 = 0.0146 m :con. of 1 CSscanned with CamScanner Cat = 0.0146 m OH = Rx 0.0146 m = 0.0290

Ksp = 0.0146 m) 6.oggen = 0.0000 124 = 1.24 xios Teial 3 ne of dil. HCI added = 3:5mi - 0.00354 volume of con of dil. Hal 1 = 0.04m me of cacoH), soln. added = 5ml = 0.005 L moles of HCl = cxv . = 0.04 0.0035L = 0.00014 moles HOI holes of cacolt), = 0.00014 moles non of CaOH) - 0.00007 moles como = no. of moles of caroto - volume of soln.in litre. = 0.00007 moles 120 .005L - 0.014 m con of cart = 0.014 m. con. of OH = 2X0.014 M = 0.028m. Ksp = 0.014 * 6.02833 = 0.0000109 = 11X10% lage Ksp = 1.2 x 109 +1-24x105+11xio = 1:18 x105 CSscanned with CamScanner

aug. ksp = 1.18x105 pksp - - 109 Кso --109 (1-18810) =-64.90) = 4.928 Tabulated ksp foe CaH), = 6.5xios pKsp = -109 (6-5x106) 3-65-187) || = 5.187 % error PKP = | Espeeimental - Actual | pk sp 7100 actual prap = 1 4.928-5.187 1 5.187 X100 = 4.99% 5 % E CSScanned with CamScanner