Question

The reaction of Cr2O3 with silicon metal at high temperatures will make chromium metal 2Cr2O3(s) +3Si() 4C(1) +3Si02(s) The reaction is begun with 53.00 g of Si and 80.00 g of Cr2O3. 1st attempt Part 1 (0.5 point) Select the limiting reactant. Choose one or more: si Cr2O3 SiO2 o cr

Answer 1

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| Aus. calculate the moles of each compound. Mass of si=539 Molay mass g sº = 28 g/mol Moles of si = mass of si Molay mass of si 1.89 mol 28 g/mol Mass of C%2O3 = 80g Molar mass of Ch2O3 = 152g/mol Mole g CM₂ Oz = mass of 01203 Molar mass & Ch₂O3 so 8 = 0.53 mol - 152 g/mol Now, calculate the limiting reagent. Chemical reaction 2CH2O₂ (8) + 3 Si(s) - 4ca1 + 3 SiO₂ (3) the ratio q for limiting reagent calculate No. g moles (compound) Stochiometry Coefficient

The compound with has less value will act as limiting reagent. for si- 1.89 = 0.63 for C42 Oz - 0.53 = 0,265 Since, the value og No. q moles (compound) Stiochiometry coefficient is less for Col2O3. Therefore C4203 is a limiting reagent.

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