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If 0.0751 moles of NaOH is added to 1.00 liters of 0.130 M CH3COOH (acetic acid), what will the pH of the resulting solution

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Answer #1

concentration (M) = mole Volume (L) volume of solution - 1.00L • NOOH] = 0.0751 mol = GET 0.0751 M 1.00L (CH3COOH) = 0.180 M

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