Question

10. Volume of sample in liters 11. Molarity of NaCl solution (Show calculations.) Questions and Problems 05 A 15.0-ml sample of NaCl solution has a mass of 15.78 g. After the NaCl solu- tion is evaporated to dryness, the dry salt residue has a mass of 3.26 g. Calculate the following concentrations for the NaCl solution. a. % (m/m) b. % (m/v) c. molarity (M) Q6 How many grams of KI are in 25.0 mL of a 3.0% (m/v) KI solution? 27 How many milliliters of a 2.5 M MgCl, solution contain 17.5 g MgCl,?

Answer 1

237 e In Me - The weight of Nael 23.269 B The weight of Nael kolution: 15.789 The volume of Nael solution: 15ml 1 a) % (m/m). mass of Nael mass of Nael sitio 3.26 mm 100 1 * 15-78 32 b) le (W/ mass of Nach The Boleme of Nach with Nort station Ping g be 3.26 T X100 © = 21.73 % Molecular weight of Nael = 58. 59/mol 3.269 at Naciz 3.26 mol Nac/ton to d 0.056 mol Nacl sb 1895 Molarity (M). moles of Nael Volume of Nacl solution in e 0.05% Aste Ideo 0.056 758188 (M) 3.7 (M)

Q2.61 34(M) past 34. (m) KT solution - 3 gof KI presents in loomh Solutions 100 ml solution contain 39 KI. 25 mb « » (2 825) aki Auto 9.6.759 KT 2 = 750 mg KIN .; 6.750 KI contain in 25 mh of 34. () KI solution. 2.71 2.5 (M) Mgela solution - 2.5 males of Mgely present in 1000 mah solution Molecular weight of jg dk = 95.23 Yanvi 17.59 of Mgelz = It's mol of Macla .: = 0.184 mol of Mace. w e could 25 moles of Macta present in 1000 mh solution 6.184 miles of sugalz m: mo re v0-189) mh 373.6 Mb t. 786 ml of 7.5 (M) Mgcla balulian cobain 1752 Mack.