Question

How many atoms or ions of each element are in 151.1 g of the following substances? (a) H2 x 1025 H atoms (b) Ca(NO3)2 * 1023 Ca2+ ions x 1024 NO3 ions (C) N202 x 1024 N atoms * 1024 O atoms (d) K2SO4 * 1024 K+ ions * 1023 s042-ions

Answer 1

troles ole of any substance Contain 6.012 X 1023 number of atom/molecul 1 mole = 6.022x102 now mole = gives weight molar mass So number of mote files for at moles of molar wight h = 2g/mol moles given a 151/ _ 75.55 molar - number of th = 75.55X6.012xios = usu.9621X1023 4,S5 X 10th H2 H so number of H = 2 X no of th - 29.10 X 1025 H 2 (6) Ca(NO₃)₂ [mal wt = 164.08 L moles = 151.1 164.08 boa 0.92 moles plat + 2NO3 => ca (103) Ica (NO₂) produce I mole Ca2+ - and 2 mole Nog

0.92 mole Ca(NO₃)2 - and 1. 84 mol Hog- produwono cat N of Ca ²+ = -= 0.92x6.022x10 5.54 XiO² Ca²+ ion Nof NO = 1.84 X 6.022 X 10" _11.08 X10?_NO, ie = tolo 8 x 1024 No-ion Imol weight = 60 glamol) 15 l./ = 2.518 o NO, moles = note Imole NO 2N+20 N₂O have a mole N and 2 mole o so 2.518 mole NO have 5.036 mole N and 5.036 molo Numer N = 5.036 x6.02?x10? = 30.32 X 10?3 = 3.032 X 1024 I Number of o= 3.0 32 X 1024 (d) kaso [mol wt = 174.29/mo mole = 151 0.867 12742 k so akt & sou

Imol of kson have owy have Imol of k 2 mol of k and 0.864 mole of ksoy have 1.734 mole kt and 0.867 mál so, 2- So no. of kt = 1.7 34x6.021 X 1023 = 10.4 4X1023 or 1.044x1024 no of sou2 = 0.867 X 6.02xio ='5. 22 X10 23