Question
You have standardized your KMnO4- solution and the molarity is 0.03251M. You used 17.98ml to reach equivalence point with your iron unknown. You started with 1.112g of unknown. What is the %Fe2+ in your unknown? (Fe2+ atomic weight=55.847 g/mol, KMnO4- formula weight= 158.03g/mol)

You have standardized your KMnO4-solution and the molarity is 0.03251M. You used 17.98ml to reach equivalence point with your
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Answer #1

Balanced Egh for this titration is 8 MnO4 + 5 Fe 2+ + 8H+ + M, 2 + + 5 Fe3+ + 4H₂O I No of moles of Mnoy = No of moles of KMn- Now 1 mole Mn Oy requires 5 moles Fe 2+ Too No of moles of Fe2+ = 0.0005816 mol 85 - = 0.002908 mol Loe Mass of Feat in sam

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