Question

Given below are data from a previous year. The Ksp is independent of [NaOH] while the solubility of Ca(OH)2 decreases as the [NaOH] increases. Explain why this is the case.

UOIT CHEM 1020, W19. Exp. 1-16.95 of Ca(OH), decreases as the (NaOH) increases. Explain why this is the case. solubility of Carol (NaOH) - O mol L- Solubility /mol L (NaOH) -0.0127 mol L Solubility K (NaOH) -0.0252 mol L NaOH) -0.0509 mol L mol L- Solubility 2.35E-02 5.2E-05 1.94E-021 5.1E-05 1.59E-02 molt Solubility K 2.35E-02 /mol 5.2E-05 1.95E-02 5.1E- 0 2.36E-02 1.08E-02 5.7E-05 5.2E-05 1.59E-02 5.3E-05 1.89E-02 5.2E-05 1.09E-02 4.8E-05 1.50E-02 5.7E-05 2.38E-02 5.4E-05 1.90E-02 4.9E-05| 4.5E-OS 1.08E-02 5.7E-05) 2.34E-02 5.1E-05 1.90E-02 1.05E-02 5.4E-05 4.9E-05 2.42E-02 5.7E-05 9.95E-03 5.0E-05 2.41E-02 5.6E-05 2.35E-02 5.2E-05 2.31E-02 5.0E-05 2.43E-02 5.7E-05 2.31E-02 5.0E-05

Answer 1

2 + Ca(OH)₂ = Ca²t+ 2 014 NaOH :-> Natt ÖH - Ca (OH) is weak electrolyte so passtically dissounte, - NaOH is strong base so completely dissolute to give Nat & Oh ions. a): The bhions from NaOH cause. Common Ion effect and result in decrease of solubility of calor) -> Q5 Ksp = [ca?"] [61] is constant for calor , Af you increase concentration of Lor] by adding NaOH, the concentration of [Ca 2+] bu solution will decrease to keep Ksp constant. as concentration of la?+ ] decreases and de to equilibrium shift backward ( towards reactant)., which result in Ses Scanformation of more Ca (OH)₂ (preupitation Scanner

- You can explain by Le chatelier's Poinüple, . which state, If you but stress on : a system; equilibrium will shift in such a way that it can minimize the effect of stres. JUU Here you are putting stress on system by changing concentration of Cor ] .. which is result of addition of NaOH. therefore equilibrium shiff to ward dieactant to minimize the concentration Stoesse Kip [ca?!] Com?? a ksp a constant. Tohl increase. Leart] decreases formation of щ оте Со (оң), (mean's solubility of Calol); decreases) Scanned with CamScanner