What is the %(m/m) of a solution containing 25.7 g of lithium fluoride (LiF) dissolved in...

Question

Question

What is the %(m/m) of a solution containing 25.7 g of lithium fluoride (LiF) dissolved in 79.3 g of water?

Answer 1

Answer #1

To calculate %(m/m) (mass percentage) of a solute, the formula used is:

%(m/m) = Mass of solute Total mass of solution - X 100%

Here, solute = LiF , solvent = water

So, mass of solute = 25.7 g

Mass of solution = mass of solute + mass of solvent = 25.7 g + 79.3g = 105 g

So, putting the values, we get:

%(m/m) of LiF = (25.7 / 105) x 100 % = 24.48 %

Answer 2

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