Question

A: 72-11=55/12=4.58 (46) 72-17-(4+120) = 7 (Remaining H) CuHgO B: 74-10-57/12 -4.75 (46) 74-17-(4 V120) = q (Remaining (1) CG HIGO Molar Mart 72/ mm Line Drawing 1. (1 pt) Draw structure of the unknown in the box at the right 2. (0.5 pt) Use the numbers provided on the C NMR spectrum to label each carbon in your structure. 3. (0.5 pt) Assign the signals labelled on the IR spectrum. Unknown: 0-32 Molar Mass 74 g/mol 4. (1 pt) Draw structure of the unknown in the box at the right Line Drawing 5. (0.5 pt) Use the numbers provided on the C NMR spectrum to label each carbon in your structure. 6. (0.5 pt) Assign the signals labelled on the IR spectrum. B: Conclusion (0.25 pt): on Thorofore the crade shant must be your own work ie your own calculations

need help with 1,2,3,4,5,6 please and thanks

Answer 1