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Question 5 (1 point) Saved The rate law for the mechanism below is A260) = 2A K1, fast Bu + 2A - A2B K2, fast A2B + Bus -- 2A
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Answer #1

The rate of the reaction is determined by the slowest step in its mechanism.

For, any mechanism the rate is determined by the concentration of the reactants.

Therefore, rate = k3[A2B][B]

Here, k3 is the rate constant, [A2B] is the concentration of A2B, and [B] is the concentration of B.

So, 3rd option is correct.

Please give good rating.

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