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4. The planar molecule SO3 shown below has Dzh symmetry. Oos- a) Determine the irreducible representations of the oxygen o or

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Sol. (a) and (d). Consider the triangular planer SO3 molecule.Its point group is D3h.The operation associated with D3h are E,C3,C2,S3,\sigmah and \sigma v . During the operation of E,all the three vectors retain position and hence the character is 3.During C3 all the vectores shift \chi (C3)=0. Each of the C2 axis pass through one of the vectors and hence \chi (C2) =1.The S3 axis coincide with the  C3 and hence \chi (S3)=0.As the \sigma h passes through all the vectors, \chi (\sigmah) =3.Each \sigma ​​​​​​​v passes through one vector and so \chi (\sigma​​​​​​​v) =1. and so on.

The irreducable representation below are labelled for the oxygen orbitals,

DonE 213 3C2 on 25 30r. Texoll FPgsd 3 3 0 0 - - 3 -3 0 0 - - - - - til 43 NN - - - - 1 1 - - 1 -1 0 0 1 -1 2 -2 1 -1 -1 | o

The possible atomic orbitals are listed below.

Symmetry species A1' E'
Atomic orbitals s px,py
  d_{z^{2}} d_{x^{2}-y^{2}}, dxy

(b) Energy 1. DVD: Napg? A2 (20) A 2 E(BR13 py) A B 192_ 16th 11th I == A2/2px) Airpy) **PP3) E (2px? Elapy E (203) ERP3) A las E(d) pz orbital

(e) In SO3, 2 p\pi−d\pi bonds are present.The answer is d_{x^{2}-y^{2}} , dxy orbitals.

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