Question

A * Normal No Spacing Heading 1 Heading 2 PROCESSING THE DATA 1. According to your data, if the volume is doubled from 6,0 mL to 12.0 mL, what happens to the pressure? (Doubles? Triples? Halved/Reduced in half?) 2. According to your data, if the volume is halved from 14.0 mL to 7.0 mL, what happens to the pressure? (Doubles? Triples? Halved/Reduced in half?) 3. From your answers to the first two questions and the shape of the curve in the plot of pressure versus volume, do you think the relationship between the pressure and volume of a confined gas is direct or inverse? 4. Which expression (k-P/V or k-P.V) corresponds to the relationship between pressure and volume? This represents Boyle's law. (Hint: plug in some of the values in graph 7, then see, whether P/V or P.V gives you reasonably constant (k) values).

Answer 1

1. From data Volume = V, Pressure = P From the given data Vi = 6ml, Pi=x atm V2 = 12ml P2 = ? atm Therefore substitute these values in the Boyle's law equation P V1 = P2V2 (xatm) (6ml) = (P2)12ml P2 = xatm/2 = 0.5x atm. Therefore pressure is halved. If volume is doubled then pressure is halved. 2. From data Volume = V, Pressure = P From the given data V1 = 14ml, P1 = x atm V2 = 7ml P2 = ? atm Therefore substitute these values in the Boyle's law equation P, V = P2V2 (xatm) (14ml) = (P2)7ml P2 = 2xatm. Initial pressure x, final pressure 2x. Therefore pressure is doubled. If volume is halved then pressure is doubled. 3. If volume is doubled then pressure is halved. If volume is halved then pressure is doubled. so pressure is inverse to volume. Va

4. Boyle's law At constant temperature, the volume of a sample of a gas varies inversely with the pressure. va V = PV = Constant Mathematically, it can be written as P.V1 = P2V2