b. Use numbers to represent curved arrows to show how the carbocation intermediate reacts with Nu:-...

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b. Use numbers to represent curved arrows to show how the carbocation intermediate reacts with Nu:- to form the electrophilic

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Answer 1

Answer #1

The mechanism of given electrophilic aromatic substitution is as follows,

H EHE 102 + Ne: - Ca HSE

Here the first number is the atom or bond where the curved arrow starts and second number is atom or bond where the curved arrow ends.

The abstraction of a proton by the nucleophile is represented as 102 , where 10 is the atom (nucleophile) from which the curved arrow starts and 2 is the atom ( H ) where the curved arrow ends.

Simultaneously a bond shift occurs which is represented as 34, where 3 is the bond from which the curved arrow starts and 4 is the bond where the curved arrow ends.

Thus we get the electrophilic aromatic substitution product C6H5E.

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