Question

2) Give the mass in micrograms of 465 molecules of carbon dioxide. sed 29T].5 299799b TTT 15 m6912 01 299799b 15 1916w biupil lo zm visvitoog291 og 2910lb 0,00.1.81.0 915 5912 bn. 1935.9 0.08 i 1916w to notauit to 1698 st no g165 0.0NC i 1936W to nois leweris ad svig 19dinemo [290]sv 92901 lo lls 92 o been son ysm 3) How many molecules are there in 37.6 kg of ethanol (C2H60)?

Answer 1

1 mole occupies avagadro no of molecules i.e

1 mol ----------------------> 6.022*1023 molecules

? ---------------------------------> 465 molecules

=> 465 * 1 / 6.022*1023

=> 7.72168*10-22 moles

mass = moles * molar mass

for CO2 = 7.72168*10-22 mole * 44 g/mol => 3.39754*10-20 grams

answer => 3.39754*10-17 mg

37.6 kg => 37600 grams

moles = 37600 g / 46.07 g/mol => 816.15 moles

molecules => 816.15 moles * 6.0221023 molecules / 1 mol => 4.915*1026 molecules

answer => 4.915*1026 molecules