the reaction is N2O4(g) <=======> 2NO2(g)
equilibrium constant = 0.48 = [NO2(g)]^2/[N2O4(g)]
a) equilibrium concentration of N2O4 = 0.15 molL^-1
concentration of NO2 = sqrt(0.48*0.15) = 0.27 molL^-1
b) concentration of NO2 = 0.25 molL^-1
concentration of N2O4 = 0.13 molL^-1
At 100°C the equilibrium constant for the following reaction is 0.48. N,0.9) = 2NO, (g) a...
Consider the reaction between NO and Cl2 to form NOCl: 2NO(g)+Cl2(g)⇌2NOCl(g) A reaction mixture at a certain temperature initially contains only [NO]= 0.67 M and [Cl2]= 0.65. After the reaction comes to equilibrium, the concentration of NOCl is 0.15 M. Find the value of the equilibrium constant (Kc) at this temperature. Express your answer using two significant figures.
23. The rate constant for a particular reaction is 27 activation energy for the reaction in kj/mol (R at 75 lut 25°C and 6 8.314 J/ mol.K) What is the 24. Initial rate data were obtained for the following reaction: A(g) + 2B(g) C + D(e) initial initial TA, mol/l. [B], molt initial rite Experiment 0.45 0.15 0.30 0.15 0.10 0.10 0.20 1.8 0.9 What are the rate law and k value for the reaction? 25. A mixture of 0.100...
5. The equilibrium constants for the following reactions are known 2NO(g) N(g)+ O(g) Ki-2.4x 100 2NO(g)+ O:(g) in 2NO:(g) K2=2.4 102 a) Sum these reactions to obtain the reaction. (10p) N2(g)+20(g) 2NO (g) b) Use the equilibrium constants of the first two reactions to determine the equilibrium. constant for the last reaction. (10p) oitei mundil Some Formulas K,-Peosbesto P(reactants) K= [products [reactants Rate = k[A]"[B]T R 0.08206 L atm/K mol R-8.314 J/mol K CHEM-1043-PO02
The equilibrium constant, Kc, for the following reaction is 6.50×10-3 at 298K. 2NOBr(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 11.1 L container at 298K contains 0.376 mol of NOBr(g) and 0.396 mol of NO, the equilibrium concentration of Br2
Consider the reaction between NO and Cl2 to form NOCl: 2NO(g)+Cl2(g)⇌2NOCl(g) A reaction mixture at a certain temperature initially contains only [NO]= 0.65 M and [Cl2]= 0.53. After the reaction comes to equilibrium, the concentration of NOCl is 0.25 M . ---Find the value of the equilibrium constant (Kc) at this temperature. Express your answer using two significant figures.
The equilibrium constant, Kc, for the following reaction is 6.50X10-3 at 298K. 2NOBr(g) =2NO(g) + Bra(g) If an equilibrium mixture of the three gases in a 11.0 L container at 298K contains 0.270 mol of NOBr(g) and 0.214 mol of NO, the equilibrium concentration of Bra is M. Submit Answer Retry Entire Group 6 more group attempts remaining
The equilibrium constant for the reaction: 2NO(g) + Br2(g) <----> 2NOBr(g) is Kc = 1.3x10^-2 at 1,000 Ka.) At this temperature, does the equilibrium favor the product or reactants?b.) Calculate Kc for 2NOBr <----> 2NO + Br2c.) Calculate Kc for NOBr <----> NO + 1/2Br2
The equilibrium constant, Kc, for the following reaction is 7.68×10-3 at 307 K. 2NOBr(g) 2NO(g) + Br2(g) Calculate Kc at this temperature for the following reaction: NO(g) + 1/2Br2(g) NOBr(g)
The equilibrium constant for the following reaction is 1.20x102 at 500K. PCI5(g) PCl3(g)+ C2(g) If an equilibrium mixture of the three gases at 500K contains 2.17x102 M PCI5(g) and 1.71x10 M PCI3, what is the equilibrium concentration of Cl2? М The equilibrium constant for the following reaction is 6.50x103 at 298K 2NOBR(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases at 298K contains 2.15x102 M NOBr(g) and 2.00x102 M NO, what is the equilibrium concentration of Br2?...
The equilibrium constant, Kc, for the following reaction is 5.19×10-3 at 286 K. 2NOBr(g) <-->2NO(g) + Br2(g) Calculate Kc at this temperature for the following reaction: NO(g) + 1/2Br2(g) <-->NOBr(g) Kc=?