If 35.0 g each of iron and chlorine react, how much FeCl3 will be formed?

Question

Question

Answer 1

Answer #1

2Fe + 3Cl₂ - 2e clz moles of fe= 35.0g = - 567 mol 0n 625 mol moles of Cla= 3500g = oryg3 mol 71 gmol dimiting reagent is cal

Answer 2

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