Question

Ethanol/T-butanol ATF (°C) y = 5.2593x R2 = 0.8149 0 0.2 0.4 0.6 1 1.2 1.4 1.6 0.8 Molarity (m)

From the graph, determine the freezing point depression constant ?? for t-butanol.

Interpret the molality versus ∆?? graph. What are the trends that you see?

If you were asked to redo Experiment 3: Freezing point depression of t-butanol, what would you modify to get better time versus temperature data?

Answer 1

Aழ___(92_one the molality e TCSolveort) - Ts (mixtese. . . 1 ks c = 0TE , Szeg Kha Depression constant o from the graph . case-11 m = 0.66 OTA = 17 lease II: m=0.8 DTA = 4 pase - ME 1 OTA = 6.6 dase-o , ma .2 . OTR = 7,7 efore I me li4 OTA = 7 then them othem then , then KA=2.84 kara 5 KA= 6.6 KA= 6.4 KA = 5 youe we com say the KA value Alostly increase and after their maximum point it becresed. . maximum aut mal ATA-6.6. Trends! on imeseesing the moeality, Ainetaly Kits increlise and sereh its maxima . after maximum potest on in welping the value. Ons molality Kith valle decreabedo ya We redo this esepertment ,' the Breezing point depression Ost-Beltemoe will be decreased at the critical temp. After this temp, if we increased the time a then we temp will remouth conszent. The Freezing point of t-Butemal is =25.510 Because oet initially with the inercusing on time, the temp. of mixtuse o increased, Hence the OTA value will be decreased at a time t-Butanol breezed, after that the temp Remain constent Hence, to SPA vaure will be byensively proportional to time Lar the Otticou teme, alater that Ota doute Remas constead, untill boe increased the time...