Question

What is the empirical formula of a compound that contains 20.0 g carbon and 6.71 g hydrogen?

What is the empirical formula of a compound that contains 20.0 g carbon and 6.718 hydrogen? Please show work and include units as how you arrive to your answer. BIVAA. IEE 2 i XX, E - 2 V TT 12p . Paragraph HD 1080

Answer 1

solution given, mass of carbon (c) = 20g mass of hydrogen (H) = 6-71g As we know molar mass of carbon (C) = Rg/mole molar mass of Hydrogen (H) = 1 g/mole 1st step-) of convert mass of carbon and hydrogen to moles of carbon and hydrogen moles of carbon (C) = mass of carbon molar mass of carbon २०१ Rg/mal .= 1.67 mal moles of hydrogen (H) = mass of hydrogen . molar mass of hydrogen 6.71g Ig/mol = 6.7 mol 2 Step-) lowest number of Divide each mole value by the moles calculated above. 1.67 mal Carbon (C) - 1.67 mol Scanned with CamScanner

6.71 mol Hydrogen = 1.67 mal 4.0179 = 3 Step round to nearest whole number Call H=4 - Empirical formula is Ansi: Chu Ghu or Chu - Scanned with CamScanner