What is the molality of a chlorine solution of 16.1 g of Cl2 dissolved in 1500...

Question

Question

Answer 1

Answer #1

No. of moles of Cl2 = (16.1 g) / (70.9 g/mol) = 0.227 mol

volume of water = 1500 mL (since density of water = 1 g/mL)

So; volume in Liter = 1.5 L

olarity = No. of moles / volume of water in Liter = (0.227 mol) / (1.5 L) = 0.15 M

Answer 2

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