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(1) When calibrating a glass electrode, 0.025 M potassium dihydrogen phosphate/0.025 M disodium hydrogen phosphate buffer...
When the difference in pH across the membrane of a glass electrode at 25 degree C...
When the difference in pH across the membrane of a glass electrode at 25 degree C is 4.40 pH units, how much voltage is generated by the pH gradient? (F = 96485 C/mol; R = 8.3145 J/mol K) mV (three significant figures) (b) What would the voltage be for the same pH difference at 37 degree C? (F = 96485 C/mol; R = 8.3145 J/mol K) mv (three significant figures) When calibrating a glass electrode, 0.025 m potassium dihydrogen phosphate/0.025...
Calibration of a glass electrode gave a reading of 134.9 mV with a 0.05 m potassium...
Calibration of a glass electrode gave a reading of 134.9 mV with a 0.05 m potassium hydrogen phthalate buffer standard (pH = 4.015), and a reading of -163.2 mV with a 0.01 m borax buffer standard (pH = 9.139), both measured at 30°C. What is the observed slope (mV/PH unit) of the calibration curve? slope observed = mV/PH What is the theoretical slope at 30°C? slope theoretical = mV/pH What is B, the electromotive efficiency, to three significant figures? B...
8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and...
8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and 0.0100 moles of potassium hydrogen phosphate (K2HPO4) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? a) The pH of the solution will decrease by a large amount ( > 0.10 pH units) b) The pH of the solution will decrease by a small amount (< 0.10 pH units) c) The pH of the solution...
7) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH PO4)...
7) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH PO4) and 0.0100 moles of potassium hydrogen phosphate (K,HPO4) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? a) The pH of the solution will increase by a small amount (< 0.10 pH units) b) The pH of the solution will increase by a large amount (> 0.10 pH units) c) The pH of the solution...
8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and...
8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and 0.0100 moles of potassium hydrogen phosphate (K2HPO4) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? The pH of the solution will decrease by a large amount ( > 0.10 pH units) The pH of the solution will decrease by a small amount (< 0.10 pH units) The pH of the solution will be exactly...
urgent 8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH,PO)...
urgent
8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH,PO) and 6-0100 moles of potassium hydrogen phosphate (K_HPO.) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? a) The pH of the solution will decrease by a large amount (>0.10 pH units) b) The pH of the solution will decrease by a small amount (<0.10 pH units) c) The pH of the solution will be...
(1 point) Calculate the pH of a buffer that is 0.0500 M in potassium hydrogen phthalate (KHP) and 0.150 M in potassium...
(1 point) Calculate the pH of a buffer that is 0.0500 M in potassium hydrogen phthalate (KHP) and 0.150 M in potassium phthalate (K2P).
7) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and...
7) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and 0.0100 moles of potassium hydrogen phosphate (K_HPO4) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? a) The pH of the solution will increase by a small amount (< 0.10 pH units) b) The pH of the solution will increase by a large amount > 0.10 pH units) c) The pH of the solution will...
thank you Describe how you would calculate the pH of the following 0.10 M aqueous solutions:...
thank you
Describe how you would calculate the pH of the following 0.10 M aqueous solutions: (a) sodium monohydrogen phosphate (b) glycine hydrochloride (c) trisodium citrate For example: treat as monoprotic acid and use Kai; treat as intermediate form and use Ka, Ka... Find the pH of a solution prepared by dissolving 1.00 g of potassium hydrogen phthalate (204.221 g/mol) and 1.20 g of disodium phthalate (210.094 g/mol) in 50.0 mL of water. (pKai = 2.950, pK2 = 5.408) The...
A buffer solution is able to maintain a constant pH when small amounts of acid or...
A buffer solution is able to maintain a constant pH when small amounts of acid or base are added to the buffer. Consider what happens when 1 mL of a 5 M solution is added or 0.005 mol of HCl are added to a 100.0 mL solution acetic acid buffer that contains 0.0100 mol of Acetic acid, HC,H,O,, and 0.0100 mol of sodium acetate, NaC,H,O,. The initial concentration of both the acid and the base are 0.0100 mol/ 0.1000 L...
When the difference in pH across the membrane of a glass electrode at 25 degree C is 4.40 pH units, how much voltage is generated by the pH gradient? (F = 96485 C/mol; R = 8.3145 J/mol K) mV (three significant figures) (b) What would the voltage be for the same pH difference at 37 degree C? (F = 96485 C/mol; R = 8.3145 J/mol K) mv (three significant figures) When calibrating a glass electrode, 0.025 m potassium dihydrogen phosphate/0.025...
Calibration of a glass electrode gave a reading of 134.9 mV with a 0.05 m potassium hydrogen phthalate buffer standard (pH = 4.015), and a reading of -163.2 mV with a 0.01 m borax buffer standard (pH = 9.139), both measured at 30°C. What is the observed slope (mV/PH unit) of the calibration curve? slope observed = mV/PH What is the theoretical slope at 30°C? slope theoretical = mV/pH What is B, the electromotive efficiency, to three significant figures? B...
8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and 0.0100 moles of potassium hydrogen phosphate (K2HPO4) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? a) The pH of the solution will decrease by a large amount ( > 0.10 pH units) b) The pH of the solution will decrease by a small amount (< 0.10 pH units) c) The pH of the solution...
7) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH PO4) and 0.0100 moles of potassium hydrogen phosphate (K,HPO4) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? a) The pH of the solution will increase by a small amount (< 0.10 pH units) b) The pH of the solution will increase by a large amount (> 0.10 pH units) c) The pH of the solution...
8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and 0.0100 moles of potassium hydrogen phosphate (K2HPO4) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? The pH of the solution will decrease by a large amount ( > 0.10 pH units) The pH of the solution will decrease by a small amount (< 0.10 pH units) The pH of the solution will be exactly...
urgent
8) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH,PO) and 6-0100 moles of potassium hydrogen phosphate (K_HPO.) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? a) The pH of the solution will decrease by a large amount (>0.10 pH units) b) The pH of the solution will decrease by a small amount (<0.10 pH units) c) The pH of the solution will be...
7) A buffer solution is formed by adding 0.0100 moles of potassium dihydrogen phosphate (KH2PO4) and 0.0100 moles of potassium hydrogen phosphate (K_HPO4) into 1.000 liters of water. When 0.0010 moles of NaOH is added to this solution, what will happen? a) The pH of the solution will increase by a small amount (< 0.10 pH units) b) The pH of the solution will increase by a large amount > 0.10 pH units) c) The pH of the solution will...
thank you
Describe how you would calculate the pH of the following 0.10 M aqueous solutions: (a) sodium monohydrogen phosphate (b) glycine hydrochloride (c) trisodium citrate For example: treat as monoprotic acid and use Kai; treat as intermediate form and use Ka, Ka... Find the pH of a solution prepared by dissolving 1.00 g of potassium hydrogen phthalate (204.221 g/mol) and 1.20 g of disodium phthalate (210.094 g/mol) in 50.0 mL of water. (pKai = 2.950, pK2 = 5.408) The...
A buffer solution is able to maintain a constant pH when small amounts of acid or base are added to the buffer. Consider what happens when 1 mL of a 5 M solution is added or 0.005 mol of HCl are added to a 100.0 mL solution acetic acid buffer that contains 0.0100 mol of Acetic acid, HC,H,O,, and 0.0100 mol of sodium acetate, NaC,H,O,. The initial concentration of both the acid and the base are 0.0100 mol/ 0.1000 L...
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