Week 7: Homework problems - Equilibrium 1) Given the reaction A+B= C+D a) Find the equilibrium...
Lab Exercise #2: Equilibria Problems 1.2S02e) 22S03(e) at 1500 K: If the equilibrium concentrations are [SO2] = 0.424 [ 2. We place 10.0 moles of N20 into a 2.00 L flask at 300 K. At equilibrium 2.20 moles remain. O2]-0.212 [SO3] = 0.076, find the Kc Given the following reaction, what is the Kc and the concentrations of N2 and O2? 3. Indicate whether the reaction will proceed right or left, and which concentrations will decrease or increase: 2HI(g) 근...
Given the chemical reaction below, A(aq) + 2 B(aq) ⇌ C(aq) + D(l) When 3.2 mol of A was mixed with 0.8 mol of B in a 1.00 L flask, 2.3 mol of C was formed at room temperature. What is the value of the equilibrium constant, Kc? Only enter the numerical value with three significant figures in the answer box below.
Given the chemical reaction below, A(aq) + 2 B(aq) ⇌ C(aq) + D(l) the equilibrium constant for the reaction is Kc = 0.8. The reaction mixture at equilibrium contains 1.47 mol of A, 1.84 mol of B in a 1.00 L flask. What is the concentration of C in the equilibrium mixture? Only enter the numerical value with three significant figures in the answer box below. Do NOT type in the unit (M).
Part A)The reversible chemical reaction . A+B⇌C+D has the following equilibrium constant: Kc=[C][D][A][B]=2.6 Initially, only A and B are present, each at 2.00 M. What is the final concentration of A once equilibrium is reached? Part B) What is the final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M ? Express your answer to two significant figures and include the appropriate units.
The reversible chemical reaction A+B⇌C+D has the following equilibrium constant: Kc=[C][D][A][B]=2.0 Part A Initially, only A and B are present, each at 2.00 M. What is the final concentration of A once equilibrium is reached? Express the molar concentration numerically using two significant figures. Part B What is the final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M ? Express the molar concentration numerically using two significant figures.
Q(22) Kp=Kc when? A) The reaction is at equilibrium B) The reaction is exothermic C) The reaction is endothermic D) all of the gasses present are at the same temperature E) the number of moles of gas on both sides of the balanced equation is the same. Q(23) HAH +A at the equilibrium (HA) = 1.65* 10-2 M and [H") = (A-) = 5.44*10-4 M at equilibrium. Kc = A) 1.7 X 10-1 C) 1.7 X 103 D) 1.7 X...
Write the equilibrium-constant expression for the reaction A(s)+3B(l)<------->2C(aq)+D(aq) in terms of [A], [B], [C], and [D] as needed. Kc=? *Kc, which is sometimes symbolized as Keq, denotes that the equilibrium constant is expressed using molar concentrations. For this question, Kc means the same thing as Keq.
a) The equilibrium constant, Kc, for the following reaction is 9.52×10-2at 350 K. CH4(g) + CCl4(g) -> 2 CH2Cl2(g) Calculate the equilibrium concentrations of reactants and product when 0.251 moles ofCH4and 0.251 moles of CCl4are introduced into a 1.00 L vessel at 350 K. [ CH4] = M [ CCl4] = M [ CH2Cl2] = M b) The equilibrium constant, Kc, for the following reaction is 1.20×10-2 at 500 K. PCl5(g) ->PCl3(g) + Cl2(g) Calculate the equilibrium concentrations of reactant...
help please 1-4 consider the reaction A+B 3 C + D. which has an equilibrium constant, K, equal to 3.4 x 10. 1. IT one begins a reaction by placing 0.600 moles of A in a 1.0L container as well as 0.150 moles on , what will be the equilibrium concentrations of A.B.C. and D? Write your answers in the spaces provided below. a. (A) = b. [B]= = C. (C)= d. (D)= 2. Once the reaction in problem 1...
At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant, Kc. 3 A(g) + 2 B(g) = 4C(g) Kc = 2.93 x 1015 If, at this temperature, 1.40 mol of A and 3.90 mol of B are placed in a 1.00 L container, what are the concentrations of A, B, and C at equilibrium? [A] = 0 B) = 1.8667 [C] = | 2.967