Problem 5 (8 points). The percent ionization for 1.0x10-ⓇM of a week monoprotic acid is 70%...

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Answer #1

solution ©). Given HA (29) + H2010 THAY = 1.0X10-3M of of ionization = 70 = A call + H30 tag) [A-] given by 6% of ionization

Answer 2

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