Question

1 of 5 below). Nur Product Spectra other reaction and on Product Spectra triplet PPM The mechanism for the reaction is:
Use the following reaction scheme and product H NMR to answer 5 different questions (Question 1 of 5 below). ņ a Creations Th
reaction quartet PPM The product for the reaction above is: OCH3 OH
singlet PPM The most likely nucleophile for the above reaction is: ОСНОН ОкоtBu NaOEt OOH он20
Product Spectre The above reaction most likely included: Polar Aprotic Solvent High Temperature Low Temperature Transition St
PPM Which leaving group would have given the fastest reaction rate (X - ???)? -CN -OCH -OMS
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Answer #1

From the H NMR spectra of product molecule it is seen that there are total four different types of Proton. Again in the starting molecule there was three different types of proton(excluding the proton of X). This observations indicates that extra one type of proton comes on the product from nucleophile. Since, in H NMR spectra there is a broad singlet peak at around 4.5ppm and broad singlet peak mainly for - OH group.

Now, as the starting material cinyains tertiary group. So,

The mechanism of the reaction is SN1

And the product for the given reaction is d(3-methyl-3-pentanol).

The most likely nucleophile for the given reaction is - OH-.

The given reaction most likely included: low temperature.

The best leaving group for the reaction which gives maximum rate is--- e) -OMs

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