Cation is formed by removing electrons from an element.
Anion is formed by adding electrons to an element.
The cation is X+2
Number of electrons present in cation = 36 electrons.
Since this is cation, electrons must be removed from X
This is a divalent cation, so, two electrons must be removed from
X.
Hence, number of electrons present in element X = 36 + 2 = 38
The element which has 38 electrons in its ground state = Sr
Name of the element = Strontium
PART- B
The cation is X–
Number of electrons present in anion = 36 electrons.
Since this is anion, electrons must be added to X
This is a mono-valent anion, so, one electron must be added to
X.
Hence, number of electrons present in element X = 36 – 1 = 35
The element which has 35 electrons in its ground state = Br
Name of the element = Bromine
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Spell out the full name of the compound
angchemistry.com/mydt/itemView?assignment ProblemID=1233830768offset=next 1 while Spell out the full name of the compound. Submit Request Answer Part B CH, CH, CH-CH-CH2-CH-CH2-OH Spell out the full name of the compound. Request Answ Submit Part C Submit Request Answer - Part OH CH2-CH3 Spell out the full name of the compound. Submit Request Answer Provide Feedback
What is each compound's systematic name?
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Part Spell out the full name of the compound. Submit Request Answer Provide Feedback
Part C Spell out the full name of the compound. Submit Request Answer Provide Feedback
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Name the following compounds
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