![A student mixes 40. mL of 0.10 M HBr(aq) with 60. mL of 0.10 M KOH(aq) at 25°C. What is the [OH-] of the resulting solution?](http://img.homeworklib.com/questions/31e064f0-d98b-11eb-a958-6bda186ec188.png?x-oss-process=image/resize,w_560)
Homework Answers
it is a neutralisation reaction
for complete neutralisation
No. of millimoles of Acid = No. of millimoles of Base.
the nature of resulting solution is depending upon which chemical [resent in higher in amount.
for example
No. of millimoles of Acid > No. of millimoles of Base - Solution is Acidic in nature.
No. of millimoles of Acid < No. of millimoles of Base - Solution is Basic in nature
No. of millimoles = Molarity x volume of solution( in ml)
No. of millimoles of Acid (HBr) = 40 x 0.10 = 4 millimoles
No. of millimoles of Base (KOH) = 60 x 0.10 = 6 millimoles.
since both acid and base are mono basic and mono acidic respectively .
therefore 4 millimoles of acid neutralised by 4 millimoles of base.
hence in solution 6 - 4 = 2 millimoles base is left.
conc. of OH- = Conc. of KOH.
because
[OH - ] = no of millimoles of base / total volume of solution in ml = 0.02 M
Ans. 0.02 M
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