Question

A) A chemist prepares a solution by adding 304 mg of Co(NO3)2 (MW = 182.94 g/mol) to a volumetric flask, and then adding water until the total volume of the contents of the flask reaches the calibration line that indicates 100 mL. Determine the molarity of the prepared solution.

B) Determine the mass of chloride (MW = 35.45 g/mol) in grams present in 100mL of a 0.289 M solution of aqueous FeCl3 (iron(III) chloride).

C) A beaker contains 250 mL of a 6.12 M HCl(aq) solution. Determine the new concentration of the solution after it is diluted by adding 102 mL of water to the beaker.

Answer 1

T A moles of CorNogle = 304 X10 3 = 1.66810²3 182.94 Molanty = moly - 1.668103 -0.0167 m volat 10) (3) moles of fechy & Holanty & voll lit) moles of ci = 3x Molarity & Vollet) - 3 x 0.289 X loo looo Mass -- mole X MW = 3 x 0.289 x 61 x 34-45 g = 2.99 g = 308 c) MY MAY 612 250 = M ( 250+102) M = 435M