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If 15.0 mL of 7.28×10-4 M Cu(CH3COO)2 are added to 18.0 mL of 8.90×10-5 M K2CO3,...

If 15.0 mL of 7.28×10-4 M Cu(CH3COO)2 are added to 18.0 mL of 8.90×10-5 M K2CO3, will solid CuCO3 (Ksp = 2.5×10-10) precipitate?   _____ yes or no

If a precipitate will not form, what carbonate ion concentration will cause a precipitate of copper(II) carbonate to form? If a precipitate will form, what is the minimum [CO32-] that could have been present without initiating precipitation? Assume the total volume used in the above example.

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Answer #1

Cu2+ + Con Ž u 103 hastus! ksp= 2.5x10 10 - volume 2 + Cenl. of . q ca . 15 ml x 7.28 x 10 - 33 ml. = 3.31*10-4 (M) Come of c

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