Calculate the molarity of each of the following solutions:
(a) 33.5 g of ethanol (C2H5OH) in 4.30 × 102 mL of solution
?M
(b) 22.6 g of sucrose (C12H22O11) in 78.5 mL of solution
?M
(c) 6.90 g of sodium chloride (NaCl) in 82.4 mL of solution
?M
Molarity is expressed as the number of moles of solute per volume of the solution. Molarity of the solutions given are calculated as follows
a. Molar mass of Ethanol C2H5OH= 12x2 + 1X5 + 16 + 1= 46g/mol
Volume= ml in litre= 4.30X102/1000
= .43L
No. Of moles = 33.5/46= .72
M= n/V
= .72/.43 = 1.69mol/L
b. Molar mass of sucrose = 342.3g/mol
Volume= 78.5/1000 = .0785L
No. Of moles = 22.6/342.3 = .066
Molarity= .066/.0785= .840mol/L
C. Molar mass of NaCl= 58.44g
Volume= 82.4/1000
=.0824L
No. Of moles = 6.90/58.44= 0.11
Molarity = n/v
= .11/.0824= 1.33mol/L.
Calculate the molarity of each of the following solutions: (a) 33.5 g of ethanol (C2H5OH) in...
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