Question

5.A homonuclear diatomic molecule in its molecular ground state has the following electronic configuration:

N a 1o21022032011143017 09 bo

a) What is the link order?
b) What is the multiplicity of spin?
c) What is the difference in the stability of the molecule, when ionizing it, removing an electron from the 1π_g molecular orbital or doing it from the 3Sigma_g molecular orbital

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Answer 1

Electronic Corresponding configuration mo diagram 107 150² 2 2 1 3g 1² is. - t antibinong 3G empty) + + ing antibinding 2 36 bonding 4 t the bonding # 26 antibending 4 229 ( bonding) h (100%) cantibunding t log (bonding) Cad link order a bonding electom - antibendriy election link order = 10-6 = 4 = [2 = link order (b) Multiplicity of spin = Triplet (3) - as number of unpaired election = a (in ling orbital) & multiplicity 12ng +1 = 2x2x1 + 1 = 13 – Triplet (2) Electronic configuration when election from lng is removed - lege 106 207 208² 1 IT 35g 1119 Electimic configuration when election removed from 30 = 108 108 209² 200² in 308 117² since 36g is lower in energy compare to ing, so more energy is needed to expel election from 36g compare to 'Tg. So molecule will get more unstable when 1 election is removed from 3og rather than I ITg. Also, when electron is removed from ITg, the spin of remaining molecule will be doublet (because just a unfaired election will be left) but removing election from 36g will produce quartet or doublet depending upon which election (up spin or down spin) is removed,