A merry-go-round is spinning at a rate of 5 revolutions per minute. Cora is sitting 0.5 m from the center of the merry-go -round and Cameron is sitting right on the edge, 2.0 m from the center.
What is the relationship between rotational speed of the two children?
a. Cameron's rotational speed is four times as much as Cora's rotational speed
b. Cora's rotational speed is the same as Cameron's rotational speed
c. Cora's rotational speed is four times as much as Cameron's rotational speed
d. Cora's rotational speed is double Cameeron's rotational speed
e. Cameron's rotational speed is double Cora's rotational speed
What is the relationship between tangential speeds of the two children?
a. Cora's tangential speed is double Cameron's tangential speed
b. Camerion's tangential speed is four times Cora's tangential speed
c. Camerion's tangential speed is double Cora's tangential speed
d. Cora's tangential speed is four times Camerion's tangential speed
e. Cora's tangential speed is the same as Camerion's tangential speed
Rotational speed will be same for both Cora and Cameron. It doesn't depend on the value of the distance from the center and therefore the correct option is \(b\).
The equation to determine the value of tangential speed is, \(v_{\text {Cora }}=r \omega =(0.5 \mathrm{~m}) \omega\quad\) And \(\quad v_{\text {Cameron }}=r \omega\)
\(=(2) \omega\)
Therefore the tangential speed of Cameron's is four times the Cora's tangential speed. The correct option is \(b\).
A merry-go-round is spinning at a rate of 5 revolutions per minute. Cora is sitting 0.5...