Homework Answers
pH of this solution is : 9.31
Explanation
Given : concentration of ammonia, [NH3] = 0.422 M
concentration of ammonium bromide, [NH4Br] = 0.373 M
NH3 Kb = 1.8 x 10-5
pKb = -log(Kb)
pKb = -log(1.8 x 10-5)
pKb = 4.74
According to Henderson - Hasselbalch equation,
pOH = pKb + log([conjugate acid] / [weak base])
pOH = pKb + log([NH4Br] / [NH3])
pOH = 4.74 + log(0.373 M / 0.422 M)
pOH = 4.74 + log(0.884)
pOH = 4.74 + (-0.05)
pOH = 4.69
pH = 14 - pOH
pH = 14 - 4.69
pH = 9.31
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