Question

Y SU Keep UY UYUU WUWULUNU UI purl MRS. ILUM L yive you le Water has a heat of vaporization of 43.4 kJ/mol. Determine its boiling point, in celcius at a pressure of 11.3 atm. (Input your units as C - don't bother looking for the degree symbol)

Answer 1

Answer. given, P2 = 11.3 atm; T2 = ? Hvap = 43.4 KJ motal = 43400 Jmot- Ti = 100°C = 373K, P, = latm. (Boiling at * atmospheric) pressure R= 8.314 JkImopol according to clausiuga clapymon equation – OT, <Hvap. en Pe - trap ( 1 / 3 ) om t - [+ - Relig R ln (P2/P.) 1 - 8.314 x ln (11-3/1) 7 or to - 1475 - 8.3 43400 or, tz = [0.002680 – 0.000463] or t = 0.002217 on, T2 = 451 K = ( 451273)- 178°C .; Boiling point of water at presswie 11.3 atm is 178°C. 26800.000