Calculate the molarity of each of the following solutions:
(Express your answer with the appropriate units.)
9.06 molmol LiNO3LiNO3 in 6.53 LL of solution.
0.595 molmol FeCl3FeCl3 in 966 mLmL of solution.
Molarity is defined as the moles of solute present in 1 Litre of solution.
To calculate the molarity, we need to divide the moles of solute by the volume of solution in liters.
In case 1 there are 9.06 moles of LiNO3 in 6.53 L of solution.
Molarity = moles of LiNO3 / volume of solution in liters = 9.06 mol / 6.53 L = 1.39 mol /L = 1.39 M
( M is the symbol of Molarity with the units of moles / liter)
In case 2, there are 0.595 moles of FeCl3 in 966 mL of solution. First we need to convert the solution volume from mL to L.
Solution volume = 966mL = 966/1000 L = 0.966L
Molarity = 0.595 mol/ 0.966 L = 0.616 mol/ L = 0.616M
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