Question

The bonding in XHz can be considered in terms of the interactions between the orbitals of atom X and the LGOs of the H3 fragment. For the LGOs, when X = B, the in-phase combination of H is orbitals has ai' symmetry, but when X = N, it has a symmetry. This is because: Select one: o a. NH3 has D3h symmetry, but BH3 belongs to the C3v point group o b. NH3 has C3v symmetry, but BH3 belongs to the D3h point group C. NH3 has C3 symmetry, but BH3 belongs to the Czy point group d. NH3 has C3v symmetry, but BH3 belongs to the D3d point group Save response

Answer 1

Answer: Hey dear student find the solution of your query, if you have any doubt feel free to ask. Thanks!! As we know: The hybridization of BHz is sp2 and the shape is trigonal planer H-B-H Trigonal planar Symmetry present in this compound is E, C3,3C2.0 and Oy so the point group of BHz is D3H The hybridization of NH3 is sp3 and the shape is pyramidal ΗΤΗ Н Pyramidal Symmetry present in this compound is E. C3 and ov so the point group of NH3 is C3v Hence on the bases of above discussion option number b is correct and a, c and d are wrong