Question

Q.8. Balance the following equation. _Co (NO3)2 (aq) +_(NH4)2S(aq) => _Co2S3() + _NH4NO3(aq)

Answer 1

This equation can be balanced by addition of atoms to the side Which have less number of that particular atom.

First of all balance all other atoms except O and H.

Then balance O by addition of H2O.

At last balance H by addition of hydronium ion if medium is acidic.

- CO(NO), (aq) + (ru) Scaq) - Co, S. (5) + - NHUNG all other atome encept o f H First of all balance 0 balancing g co LHS only one 26 (NO₂), (99)+ on RHS there are 2 coe on multiply by a to first. INHU). Scag) - CO₂ S₃ (S) + hyn by 2 4 to first team in LHS. @ balaning of so on RHS f one on LAS is anong ay s multiply by 3 there to are second thells term in LHS. 20(NO3)2 (aq) + 3(NH4) Scau) cos(5) + NHU Ng(aq) & Balancing on there are 10 Na 2 on RHS : multiply by 5 to 2nd hum on RHS I(NO3)₂ (aq) + 3 (NH4), Scaq) co, S₃ (8) + 5 NHL NO₂ (aq) Now Balace o by adding HHO on the side which has les number of ony gen. there are 12 onggen on LHS and is on RHS. add 3 HO on LHS. 260 (NO), (aq) + 3 (NH4) 5 (aq) + 3H20 Co (s) + 5 NM, NO₃ 104) ③ Balancing of Hydrogen As it is acidic nature of (NH4)₂S and NHU NO₃ So balancing of Hydrogen is done by addition of utions

to the side which have less number of Hydrogens. There are 30 H's on LHS & 20 it's on RHS. add 10H on RHS. - (), () + 3(-), ca 4 ) + 3H2O -> C, S, (3) + S + H , (4)+ 10 - This is balanced equation.