1)
Given:
Pi = 1.58 atm
Vi = 6.95 L
Vf = 5.75 L
Ti = 95.0 oC
= (95.0+273) K
= 368 K
Tf = 39.0 oC
= (39.0+273) K
= 312 K
use:
(Pi*Vi)/(Ti) = (Pf*Vf)/(Tf)
(1.58 atm*6.95 L)/(368.0 K) = (Pf*5.75 L)/(312.0 K)
Pf = 1.62 atm
Answer: 1.62 atm
2)
Given:
Q = 1500 J
m = 496 g
C = 0.385 J/g.oC
Tf = 47.5 oC
use:
Q = m*C*(Tf-Ti)
1500.0 = 496.0*0.385*(47.5-Ti)
47.5 - Ti = 7.855 oC
Ti = 39.64 oC
Answer: 39.6 oC
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