1) 2) 3) A particular reaction has an activation energy, Eq, of 139 kJ/mol. If the...

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1)

A particular reaction has an activation energy, Eq, of 139 kJ/mol. If the rate constant for the reaction is 0.00732 s-1 at 72

2)

4NH3 + 702 → 4NO2 + 6H20 M/S When the rate of disappearance of NH3 is 0.36 M/s , the rate of appearance of H20 is *Please rep

3)

The value of Keq for the following reaction is 0.690 A (8) +B (g)=C(g) +D (g) The value of Keq at the same temperature for th

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Answer 1

Answer #1

1)
Given:
T1 = 721 oC
=(721+273)K
= 994 K
K1 = 7.32*10^-3 s-1
K2 = 0.231 s-1
Ea = 139 KJ/mol
= 139000 J/mol

use:
ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)
ln(0.231/7.32*10^-3) = (139000.0/8.314)*(1/994 - 1/T2)
3.4518 = 16718.7876*(1/994 - 1/T2)
T2 = 1251 K
= (1251-273) oC
= 978 oC
Answer: 978 oC

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