4.17 x 1021 molecules of KOH = ______________ moles

Question

Question

Answer 1

Answer #1

According to avogadro's law 1 mole of substance contain 6.022 X 1023 molecule

therefore,

No. of moles = no. of molecule / 6.022 X 1023

No. of moles of KOH = 4.17 X 1021 /6.022 X 1023 = 0.0069246 moles

4.17 X 1021 molecules of KOH = 0.0069246 moles

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Answer 2

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