Question

Part A How many moles of sulfur are present in 3.5 moles of Al2(SO4)3? Express the number of moles to two significant figures. V AX“ o ? 0.5 moles

Answer 1

Part A = 11 moles S

Part B = 0.72 moles Al

Part C = 6.0 moles SO₄^2-

<sup>| Al2(SO4)₂ - 2 AL + S + 120 There are two moles of Aluminium, 3 moles of sulfur and twelve moles of oxygen are present. in one mole Aluminium sulfate. Part A. According to stoichiometry 1 mole Al2(SO4), contains 3 so 3.5 males Al2(SO4)₂ contains males s 3X3.5 moles s = 10:5 males s 11 moles s ar Part B. 1 mole Al2(SO4)3 sor 0.36 moles of contains Al2(504), al 2 moles contains - 2x 0.36 moles 0.72 moles Al. al

I Part C. Ala (504) - 2 Al3+ + 3 5042 According contains to 3 stoichiometry, one mole Al2(504), males of 2 SO42- ions slave ie Al2(SO4)3 contains 3 moles so 42 1 mole so 2-0 mells Alz(504) contains 3X20 moles sous 6.0 molls SO4²- -</sup>