The illustration to the left represents a mixture of oxygen (red) and fluorine (green) molecules.
If the molecules in the above illustration react to form OF₂ according to the equation O₂+2 F₂ ⟶ 2 OF₂
the limiting reagent is _______
the mumber of OF₂ molecules formed is _______ and
the number of _______ atoms molecules in excess is_______
The illustration to the left represents a mixture of oxygen (red) and fluorine (green) molecules.
The illustration to the left represents a mixture iodine (purple) and fluorine (green) molecules. If the molecules in the above illustration react to form IF, according to the equation 12 +3 F22 IF3, the limiting reagent is the number of IFz molecules formed is , and the number of atoms/molecules in excess is The illustration to the left represents a mixture iodine (purple) and fluorine (green) molecules. If the molecules in the above illustration react to form IF, according to...
The illustration to the left represents a mixture of phosphorus (orange) and fluorine (green) molecules. If the molecules in the above illustration react to form PF3 according to the equation P4+6 F24 PF3 , 8 • The illustration to the left represents a mixture of carbon (black) and oxygen (red) reacting to form a product. In the illustration: The product that forms is . The number of product molecules formed is The limiting reagent is The number of atoms/molecules in...
The illustration to the left represents a mixture of nitrogen (blue) and oxygen (red) molecules. If the molecules in the above illustration react to form N, O, according to the equation N2 +20, N204, the limiting reagent is the number of N,O molecules formed is . and the number of molecules in excess is
The illustration to the left represents a mixture of hydrogen (light blue ) and oxygen (red) reacting to form a product. In the illustration: The product that forms is The number of product molecules formed is The limiting reagent is The number of atoms/molecules in excess is
The illustration to the left represents a mixture of carbon (black) and oxygen (red) reacting to form a product. In the illustration: The product that forms is The number of product molecules formed is In the illustration: The product that forms is The number of product molecules formed is The limiting reagent is The number of atoms/molecules in exo
The illustration to the left represents a mixture of hydrogen (light blue) and iodine ( purple) reacting to form a product. In the illustration: The product that forms is The number of product molecules formed is The limiting reagent is atoms/molecules in excess is The number of
The illustration to the left represents a mixture of hydrogen (light blue ) and iodine (purple) reacting to form a product. sited In the illustration: The product that forms is The number of product molecules formed is The limiting reagent is The number of atoms/molecules in excess is
Use the References to access important values if needed for this question. It is desired to produce 6.30 grams of sulfurous acid (H2SO3) by the following reaction. If the percent yield of sulfurous acid (H2S03) is 75.6 %, how many grams of sulfur dioxide would need to be reacted? gras sulfur dioxide sulfur dioxide(g) + water(l) — sulfurous acid (H2SO3)(g) The illustration to the left represents a mixture of xenon (brown ) and fluorine (green) molecules If the molecules in...
do?l The illustration on the left represents a mixture of N ( blue) and o. (red) molecules reacting to form form NO NO: mol O: mol NO: mol NO: mol O: will be formed
Yellow-green spheres represent fluorine atoms and red spheres represent oxygen atoms, and all the molecules are gases. Reactants Actual products Part A Write a balanced equation for the reaction. Express your answer as a chemical equation. Identify all of the phases in your answer. = AE O 2 ? Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Identify the limiting reactant. Express your answer as a chemical formula. AD A 2 ? Part C...