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History Bookmarks People Tab Window Help Question 1 of 12 A weather balloon calibrated at 0.000 °C to have a volume of 100.0
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Answer #1

we can use following derived ideal gas equaiton to calculate the new volume

Va/Ta = Vb / Tb

Va = 100 L Ta =0 0C = 173.15 K Tb = -40.8 0C = 232.35  K Vb = ?

Let us substitute the vaues and calculate Vb

Vb = 100 L x 232.35K / 273.15 K = 85.06 L  

Hence the new volume of the baloon is 85.06 Liter

Option C is correct answer

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